From @masak

<masak> std​: subset A of Int;
<p6eval> std 27169​: OUTPUT«ok 00​:02 35m␤»
<masak> rakudo​: subset A of Int;
<p6eval> rakudo 1b06df​: OUTPUT«Statement not terminated properly at line 2 [...]
* masak submits rakudobug

From @kyleha

I've added a test for this in r27180 at the end of S12-subset/subtypes.t

It looks like this​:

#?rakudo todo 'bug #​66854'
eval_lives_ok 'subset A of Int;', 'subset declaration without where clause';

Kyle.

On Mon, Jun 22, 2009 at 8​:38 AM, Carl Mäsak<perl6-bugs-followup@​perl.org> wrote​:

# New Ticket Created by  "Carl Mäsak"
# Please include the string​:  [perl #​66854]
# in the subject line of all future correspondence about this issue.
# <URL​: http://rt.perl.org/rt3/Ticket/Display.html?id=66854 >

<masak> std​: subset A of Int;
<p6eval> std 27169​: OUTPUT«ok 00​:02 35m␤»
<masak> rakudo​: subset A of Int;
<p6eval> rakudo 1b06df​: OUTPUT«Statement not terminated properly at line 2 [...]
* masak submits rakudobug

The RT System itself - Status changed from 'new' to 'open'

From @jnthn

On Mon Jun 22 06​:38​:06 2009, masak wrote​:

<masak> std​: subset A of Int;
<p6eval> std 27169​: OUTPUT«ok 00​:02 35m␤»
<masak> rakudo​: subset A of Int;
<p6eval> rakudo 1b06df​: OUTPUT«Statement not terminated properly at
line 2 [...]
* masak submits rakudobug

Now works in git 1831bd1. Unfudged the test from kyle++ that checks it
parses, and added a few others to ensure that it not only parses, but
also works. So, resolving this one now.

Thanks,

Jonathan

@jnthn - Status changed from 'open' to 'resolved'