From @masak

<masak> rakudo​: enum A <a b c>; enum B <a b c>; say &a.perl
<p6eval> rakudo 1d4928​: OUTPUT«B​::a␤»
* masak submits rakudobug
<jnthn> ?
<jnthn> Heh
<moritz_> it should be ambiguous
<jnthn> Oh
<moritz_> I can never remember how to write that word :-)
<jnthn> Yeah, that.

According to S12​:1787, rather than just picking B​::a, &a should be
unavailable as a symbol, due to it being found both in A and in B.

From nastavs@gmail.com

Here's something more along the same lines.

<isBEKaml> rakudo​: enum One <a b c d e>; enum Two <a b c d e>; say &d;
<p6eval> rakudo 982e8e​: OUTPUT«Contextual $*PKGDECL not found␤current
instr.​: 'perl6;Perl6;Grammar;add_my_name' pc 44311
(src/gen/perl6-grammar.pir​:79)␤»

for sure, it's a LTA error message.

Regards,

Shrivatsan

The RT System itself - Status changed from 'new' to 'open'

From nastavs@gmail.com

On Thu May 27 01​:19​:33 2010, svatsan wrote​:

Here's something more along the same lines.

<isBEKaml> rakudo​: enum One <a b c d e>; enum Two <a b c d e>; say &d;
<p6eval> rakudo 982e8e​: OUTPUT«Contextual $*PKGDECL not found␤current
instr.​: 'perl6;Perl6;Grammar;add_my_name' pc 44311
(src/gen/perl6-grammar.pir​:79)␤»

<isBEKaml> rakudo​: enum One <a b c d e>; say One​::d.WHAT.perl; enum Two
<a b c d e>; Two​::d.WHAT.perl.say;
<p6eval> rakudo 982e8e​: OUTPUT«Contextual $*PKGDECL not found␤current
instr.​: 'perl6;Perl6;Grammar;add_my_name' pc 44311
(src/gen/perl6-grammar.pir​:79)␤»

From @coke

Current status​: mostly the same, looks like the leading & is no longer
required​:

15​:19 < [Coke]> rakudo​: enum A <a b c>; enum B <a b c>; say &a.perl
15​:19 <+p6eval> rakudo ce15be​: OUTPUT«===SORRY!===␤Symbol '&a' not
predeclared
  in <anonymous> (/tmp/JQVXYcGEKu​:1)␤»
15​:22 < [Coke]> rakudo​: enum A <a b c>; enum B <a b c>; say c.perl
15​:22 <+p6eval> rakudo ce15be​: OUTPUT«B​::c␤»

--
Will "Coke" Coleda

From @bbkr

2012.10 - still broken (should fail on redeclaration)

<bbkr_> rakudo​: enum A <a b c>; enum B <a b c>; say c.perl
<p6eval> rakudo c82d10​: OUTPUT«B​::c␤»

STD error​:

<bbkr_> std​: enum A <a b c>; enum B <a b c>; say c.perl
<p6eval> std 04216b1​: OUTPUT«�[31m===�[0mSORRY!�[31m===�[0m␤Illegal redeclaration of
symbol 'a' (see line 1) at /tmp/Ptu5rCvAvQ line 1​:␤------> �[32menum A <a b c>; enum B <a b
c>�[33m⏏�[31m; say c.perl�[0m␤Illegal redeclaration of symbol 'b' (see line 1) at /tmp/Ptu5rCvAvQ
line 1​:␤------> �[32m…

From @masak

On Thu Nov 15 05​:16​:59 2012, bbkr wrote​:

2012.10 - still broken (should fail on redeclaration)

<bbkr_> rakudo​: enum A <a b c>; enum B <a b c>; say c.perl
<p6eval> rakudo c82d10​: OUTPUT«B​::c␤»

Just for the record; no, it shouldn't fail on redeclaration (despite
STD's error message). The spec says that the a, b, and c slots become
"poisoned" and can't be used as-is anymore. They have to be specified as
A​::a etc.

From @FROGGS

Patch​: rakudo/rakudo@e340863189
Tests​: Raku/roast@fc3dc9958e

@FROGGS - Status changed from 'open' to 'resolved'