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Prefix op parsing takes precedence over subroutine parsing, should not #2832
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From @moritz10:58 < moritz> r: say not(0) + 1 But S03 says: In term position, any identifier followed immediately by a not($x) + 1 # means (not $x) + 1 |
From @usev6This is still the same as in 2012: $ perl6 -e 'say not(0) + 1' I added a test (fudged "todo") in S03-operators/precedence.t with commit Raku/roast@156e7e7 |
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From @usev6This is still the same as in 2012: $ perl6 -e 'say not(0) + 1' I added a test (fudged "todo") in S03-operators/precedence.t with commit Raku/roast@156e7e7 |
@usev6 - Status changed from 'new' to 'open' |
From @usev6This works now: $ perl6 -e 'say not(0) + 1' $ perl6 -e 'say (not 0) + 1' The test was unfudged with commit Raku/roast@0f47ac7711 I'm closing this ticket as 'resolved'. |
1 similar comment
From @usev6This works now: $ perl6 -e 'say not(0) + 1' $ perl6 -e 'say (not 0) + 1' The test was unfudged with commit Raku/roast@0f47ac7711 I'm closing this ticket as 'resolved'. |
@usev6 - Status changed from 'open' to 'resolved' |
Migrated from rt.perl.org#114210 (status was 'resolved')
Searchable as RT114210$
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