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Rakudo can't parse lexical subrule calls with arguments in regexes. #2055
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From ekiru.0@gmail.comHere's a relevant irclog: [8:58pm] pmichaud: rakudo: my regex foo($s) { $s }; say 'a' ~~ / <&foo('a')> / This also occurs with <&foo: 'a'>. For either "my regex foo($s) { $s }; say 'a' ~~ / <&foo('a')> /;" or -- |
@coke - Status changed from 'new' to 'open' |
From @ShimmerFairyBy sheer serendipity, these two bugs were rediscovered just today (see http://irclog.perlgeek.de/perl6/2014-03-13#i_8432837 and onwards). The <foo(arg)> form is fixed, while the <&foo(arg)> currently fails with this message: <lue> m: my regex foo($s) { $s }; say 'a' ~~ / <&foo('a')> / |
From @jnthnOn Thu Mar 13 19:56:42 2014, lue wrote:
This is now also fixed, along with the <&foo: ...> form. Both have tests in S05-interpolation/lexicals.t. |
@jnthn - Status changed from 'open' to 'resolved' |
Migrated from rt.perl.org#77152 (status was 'resolved')
Searchable as RT77152$
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