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SIGCHLD and qx() #9877
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From @MaikHentscheAMDPlease find the bug report generated by perlbug attached. so long -- |
From @ikegamiOn Fri, Sep 18, 2009 at 6:16 AM, Maik Hentsche <perlbug-followup@perl.org>wrote:
When you use qx() together with fork() and wait() you get unexpected
In Perl or in your code? That's debatable. You can stop stepping on qx's use strict; use POSIX qw( WNOHANG ); my %pids_to_handle; $SIG{CHLD} = sub { my $pid=fork(); |
The RT System itself - Status changed from 'new' to 'open' |
Migrated from rt.perl.org#69212 (status was 'open')
Searchable as RT69212$
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