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error in documentation for POSIX::pipe #7599
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From chris@ex-parrot.comCreated by chris@caesious.cold.localIn the documentation for the POSIX module, there is the statement, pipe Create an interprocess channel. This returns file descriptors like those returned by ($fd0, $fd1) = POSIX::pipe(); See also "pipe" in perlfunc. This is wrong. $fd0 is writable, $fd1 is readable. The file Perl Info
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From @rgschris@ex-parrot.com (via RT) wrote:
Good catch, I've done it as change 23518 to bleadperl. |
The RT System itself - Status changed from 'new' to 'open' |
@rgs - Status changed from 'open' to 'resolved' |
From @schwernOn Fri, Nov 19, 2004 at 10:48:48AM +0100, Rafael Garcia-Suarez wrote:
If you call things $fd0 and $fd1 folks are going to get it wrong. --- ext/POSIX/POSIX.pod 2004/11/19 19:25:52 1.1 - ($fd0, $fd1) = POSIX::pipe(); See also L<perlfunc/pipe>. -- |
From @petdanceOn Fri, Nov 19, 2004 at 02:28:56PM -0500, Michael G Schwern (schwern@pobox.com) wrote:
Yay Schwern! See also my rant at http://www.oreillynet.com/pub/wlg/4535 Any variable that relies on a numeral to distinguish it from a xoxo, -- |
From @rgsMichael G Schwern wrote:
Thanks, applied as #23527. |
Migrated from rt.perl.org#32486 (status was 'resolved')
Searchable as RT32486$
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