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export sub from used module is broken if make pir #333
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From @ilyabelikinHi, Example: Foo/Bar.pm: sub bar ($a) is export { say $a; } Foo.pm: use Foo::Bar; sub foo { sub test { test.pl: test(); this work, but if I make it to pir, work only test() call and "Could Example source with Makefile in attach. Thank you! Ilya osname= linux Summary of my parrot 0.7.1 (r31282) configuration: Environment: |
From @ilyabelikin |
From @moritzOn Fri Sep 19 22:45:29 2008, ihrd wrote:
I suspect that could be related to r31226 | jonathan | 2008-09-18 12:46:58 +0200 (Thu, 18 Sep 2008) | 1 line [rakudo] Make use happen at BEGIN time. This lets us use modules that Moritz |
The RT System itself - Status changed from 'new' to 'open' |
From @pmichaudOn Fri, Sep 19, 2008 at 10:45:30PM -0700, Ilya Belikin wrote:
Correct, Rakudo doesn't implement "is export" as of yet. It's one Pm |
From @jnthnOn Sat Sep 20 01:25:09 2008, moritz wrote:
Yes, it was. I've now in r32325 done something that gives us the best of Hope this helps! Jonathan |
@jnthn - Status changed from 'open' to 'resolved' |
Migrated from rt.perl.org#59104 (status was 'resolved')
Searchable as RT59104$
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