From @finanalyst

r​: my @​s=(0,1,0.5,0.4)[^3]; my @​t=((0,1,0.5,0.4) xx 1)[^3]; say @​s == @​t
<camelia> rakudo-parrot d72797, rakudo-jvm d72797​: OUTPUT«False␤»

Output should be True

((0,1,0.5,0.4) xx 1)
produces a four element list, and so does
((0,1,0.5,0.4) xx 1)[^3]

but the latter should be a three element list.

I think

Richard (finanalyst)

From @timo

My thoughts on this are as follows​:

  < timotimo> r​: .say for ((1, 2, 3) xx 2)
  <+camelia> rakudo-parrot 6d54dc, rakudo-jvm 6d54dc​: OUTPUT«1␤2␤3␤1␤2␤3␤»

since a for loop will evaluate the result of the xx operation in list context and flatten it, and the output of a .perl on it is​:

  < timotimo> r​: ((1, 2, 3) xx 2).perl.say
  <+camelia> rakudo-parrot 6d54dc, rakudo-jvm 6d54dc​: OUTPUT«((1, 2, 3), (1, 2, 3)).list␤»

the postcircumfix should flatten, too.

If you write $(1, 2, 3) xx 2 instead, it should naturally not flatten, just as the for loop wouldn't.

The RT System itself - Status changed from 'new' to 'open'

From @moritz

Hi,

On Tue Dec 24 03​:15​:50 2013, rnhainsworth@​gmail.com wrote​:

r​: my @​s=(0,1,0.5,0.4)[^3]; my @​t=((0,1,0.5,0.4) xx 1)[^3]; say @​s == @​t
<camelia> rakudo-parrot d72797, rakudo-jvm d72797​: OUTPUT«False␤»

By the current rules (changed during the Great List Refactoring), this is now correct, since @​list xx 1 produces a one-element list, and subscripting with [^3] doesn't flatten anymore.

Cheers,
Moritz

@moritz - Status changed from 'open' to 'rejected'