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Can't defer to return() #2306
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From @moritzOn Rakudo 2010.12: use v6; return $x; I'd expect that to output 3\n, but instead I get Null PMC access in clone() which is sad, because it prevents me from using a "neat" and evil trick. |
From @masakmoritz (>):
<masak> rakudo: my &r := &return; sub f { my sub return($v) { say |
The RT System itself - Status changed from 'new' to 'open' |
From @bbkrOn 2012.12: <bbkr__> r: sub f($x) { multi return($nv) { nextwith($nv /2); }; return $x; }; say f 6 |
From @cokeOn Fri Jan 04 04:38:30 2013, bbkr wrote:
Pretty much unchanged: $ perl6 -e 'sub f($x) { multi return($nv) { nextwith($nv /2); }; return $x; }; say f 6' |
1 similar comment
From @cokeOn Fri Jan 04 04:38:30 2013, bbkr wrote:
Pretty much unchanged: $ perl6 -e 'sub f($x) { multi return($nv) { nextwith($nv /2); }; return $x; }; say f 6' |
From @cokeOn Wed Jul 08 09:55:39 2015, coke wrote:
Updated behavior: $ perl6 -e 'sub f($x) { multi return($nv) { nextwith($nv /2); }; return $x; }; say f 6' -- |
Migrated from rt.perl.org#81278 (status was 'open')
Searchable as RT81278$
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