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Function syntax doesn't work on meta operators #1976
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From @markjreed
That should produce the same thing as this:
Functional notation works for named functions, just not for meta-operators. -- |
From @moritzOn Tue Jul 27 10:44:02 2010, markjreed wrote:
I'm not sure it's supposed to be as you said - after all, +(1 * 2) Could please you cite a piece of the spec that supports your claim? Moritz |
The RT System itself - Status changed from 'new' to 'open' |
From @masak<TimToady> rakudo: say [+](1,2,3) / 2; # fayl |
From @moritzworks now, and tested in S03-metaops/reduce.t |
@moritz - Status changed from 'open' to 'resolved' |
Migrated from rt.perl.org#76758 (status was 'resolved')
Searchable as RT76758$
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