From @cognominal

my @​a=<1 2 3>; @​a>>.map​: ( '(' ~ $^a ~ ')' )
Lexical '$a' not found
my @​a=<1 2 3>; @​a>>.map​: { '(' ~ $^a ~ ')' } # correct program btw
(1) (2) (3)

--
cognominal stef

@coke - Status changed from 'new' to 'open'

From @coke

On Thu Jun 17 23​:24​:28 2010, cognominal wrote​:

my @​a=<1 2 3>; @​a>>.map​: ( '(' ~ $^a ~ ')' )
Lexical '$a' not found

We've definitely backslid here​:

$ ./perl6

my @​a=<1 2 3>; @​a>>.map​: ( '(' ~ $^a ~ ')' )
Segmentation fault

my @​a=<1 2 3>; @​a>>.map​: { '(' ~ $^a ~ ')' } # correct program btw
(1) (2) (3)

--
Will "Coke" Coleda

From @jnthn

On Fri Sep 30 17​:50​:20 2011, coke wrote​:

On Thu Jun 17 23​:24​:28 2010, cognominal wrote​:

my @​a=<1 2 3>; @​a>>.map​: ( '(' ~ $^a ~ ')' )
Lexical '$a' not found

We've definitely backslid here​:

$ ./perl6

my @​a=<1 2 3>; @​a>>.map​: ( '(' ~ $^a ~ ')' )
Segmentation fault

Fixed.

my @​a=<1 2 3>; @​a>>.map​: ( '(' ~ $^a ~ ')' )
Cannot declare placeholder parameter $^a in the mainline

Thanks,

/jnthn

@moritz - Status changed from 'open' to 'resolved'