From @masak

<isBEKaml> rakudo​: my $a = 1..10; for $^a { .say }
<p6eval> rakudo 9a15b8​: OUTPUT«12345678910␤»
<masak> o.O
* masak submits rakudobug
<isBEKaml> masak​: bug? :O
<masak> rakudo​: my $a = 42; say $^a
<p6eval> rakudo 9a15b8​: OUTPUT«42␤»
<masak> std​: my $a = 42; say $^a
<p6eval> std 30748​: OUTPUT«�[31m===�[0mSORRY!�[31m===�[0m␤Placeholder
variable $^a cannot be used in this kind of block [...] FAILED 00​:01
115m␤»
<masak> alpha​: my $a = 42; say $^a
<p6eval> alpha 30e0ed​: OUTPUT«42␤»
<masak> huh.

I consider the above to be wrong, because a placeholder parameter $^a
is sufficiently different from an ordinary lexical variable $a that
the former should not be used as a synonym for the latter.

I have the feeling that this ticket might be a duplicate. However, I
haven't been able to locate the better half of this ticket; if you do,
please merge.

From @moritz

Now says
===SORRY!===
Cannot declare placeholder parameter $^a in the mainline at

@moritz - Status changed from 'new' to 'resolved'

From @moritz

Now says
===SORRY!===
Cannot declare placeholder parameter $^a in the mainline at