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'&$b()' is parsed wrongly by Rakudo #1724
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From @masak<JimmyZ> masak: alpha is diferent from rakudo |
From @cokeOn Sun Apr 25 07:22:56 2010, masak wrote:
Error has changed: 00:53 <[Coke]> rakudo: my $b = &time; say &$b(); -- |
The RT System itself - Status changed from 'new' to 'open' |
From @cokeOn Tue Aug 17 21:54:31 2010, coke wrote:
And again: 10:45 < [Coke]> rakudo: my $b = &time; say &$b(); -- |
From @moritzAm 11.01.2012 16:46, schrieb Will Coleda via RT:
The problem here is just that 'time' is implemented as a term, not as a 09:46 < moritz> nom: sub f { 6 }; my $b = &f; say &$b() likewise if I reference 'time' correctly: 09:47 <+p6eval> nom 47540c: OUTPUT«1326441971» Can be closed with tests. Cheers, |
From @moritznow tested in S02-types/sigils-and-types.t. |
@moritz - Status changed from 'open' to 'resolved' |
Migrated from rt.perl.org#74654 (status was 'resolved')
Searchable as RT74654$
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