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Can not call type conversion methods with .= in Rakudo #1408

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p6rt opened this issue Nov 20, 2009 · 4 comments
Closed

Can not call type conversion methods with .= in Rakudo #1408

p6rt opened this issue Nov 20, 2009 · 4 comments
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p6rt commented Nov 20, 2009

Migrated from rt.perl.org#70676 (status was 'resolved')

Searchable as RT70676$
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p6rt commented Nov 20, 2009

From @masak

<masak> std​: my $a; $a .= Int
<p6eval> std 29145​: ok 00​:02 109m␤
<masak> rakudo​: my $a = 5.5; $a .= Int
<p6eval> rakudo 7347ec​: .= must have a call on the right hand side at
line 2, near " .= Int" [...]
* masak submits rakuodbug

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p6rt commented Jun 6, 2010

From radu_cs85@yahoo.com

I've tried replicating this, but it seems to work ok now.Maybe this
ticket should be closed.

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p6rt commented Jan 20, 2011

From @Kodiologist

Indeed. Some tests that I just added to S03-operators/inplace.t (roast
8447ca80b) pass.

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p6rt commented Jan 20, 2011

@Kodiologist - Status changed from 'new' to 'resolved'

@p6rt p6rt closed this as completed Jan 20, 2011
@p6rt p6rt added the Bug label Jan 5, 2020
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