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S12 Tiebreaker algorithm A should dispatch to the first candidate that matches in Rakudo #1226
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From @masak<jnthn> rakudo: multi foo(:$a!, *%_) {}; multi foo(:$b, *%_) {}; foo(:a, :b) |
From @coke2+ years, still ambiguous: 10:35 < [Coke]> rakudo: multi foo(:$a!, *%_) {}; multi foo(:$b, *%_) {}; -- |
@coke - Status changed from 'new' to 'open' |
From @cokeOn Sun Oct 16 07:36:18 2011, coke wrote:
This is no longer ambiguous - test added in S06-multi/syntax.t, closing ticket. -- |
@coke - Status changed from 'open' to 'resolved' |
Migrated from rt.perl.org#68528 (status was 'resolved')
Searchable as RT68528$
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