From @moritz

I found a small piece of code that reproduces the "Null PMC access in
type()" error​:

sub f(Int $n){
  if ($n >= 0 ){
  f($n-1);
  }
}
f(0);

produces the above error on parrot + rakudo r29207, Debian GNU Linux
i386 32bit.

An even smaller example is
sub f (Int $n) { f($n-1) }; f(0)
except that this one would loop infinitely if it weren't for the null
PMC access.

--
Moritz Lenz
http://moritz.faui2k3.org/ | http://perl-6.de/

From @jnthn

On Wed Jul 09 10​:48​:19 2008, moritz@​casella.verplant.org wrote​:

I found a small piece of code that reproduces the "Null PMC access in
type()" error​:

sub f(Int $n){
if ($n >= 0 ){
f($n-1);
}
}
f(0);

produces the above error on parrot + rakudo r29207, Debian GNU Linux
i386 32bit.

I fixed a while ago the bug that prevented us seeing the real exception.
Today I have fixed the root cause of this, which was the type check
failure. So this now runs as it should (I stuck a "say $n" in and tried
it with f(4) and so forth, and it works as expected).

Thanks,

Jonathan

The RT System itself - Status changed from 'new' to 'open'

@jnthn - Status changed from 'open' to 'resolved'