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isa method errors when called on a subset type object #6510
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From @dwarringcurrent behavior of isa method on a subset: % perl6 -v The documentation https://docs.perl6.org/routine/isa implies this should |
From @AlexDanielWhat about this commit? rakudo/rakudo@0704cd9 On 2017-09-12 13:55:51, david.warring wrote:
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The RT System itself - Status changed from 'new' to 'open' |
From @dwarringAfter that commit: subset S of Int; S.isa(True) returns true as expected. I've noticed a quibble with subset of a subset: perl6 -e'subset S of Int; subset S2 of S; say S2.isa(S)' Should be True. On Sun, Sep 17, 2017 at 3:17 AM, Aleks-Daniel Jakimenko-Aleksejev via RT <
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From @dwarringTests added with roast commit One remaining todo test for the subset of a subset case, ie: subset S of Int; subset S2 of S; say S2.isa(S) On Sun, Sep 17, 2017 at 6:34 AM, David Warring <david.warring@gmail.com>
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From @dwarringFinal issues resolved with rakudo/rakudo@cee1be2 On Sat, 16 Sep 2017 12:12:35 -0700, david.warring wrote:
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@dwarring - Status changed from 'open' to 'resolved' |
Migrated from rt.perl.org#132073 (status was 'resolved')
Searchable as RT132073$
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