From @masak

<thou> are grammars known broken in current nom? e.g. this works in
rakudo-ng and not in rakudo-nom, for me​:
https://gist.github.com/1529700
<benabik> It seems to work if I set $/ to the return value of parse
<benabik> Perhaps there's a bug with $/ ?
<masak> yes, seems that way.
<masak> all the .parse calls come out as True in nom.
<masak> nom​: grammar G { rule TOP { a } }; say so G.parse("a"); say so
$/; say $/.perl
<p6eval> nom a9bead​: OUTPUT«Bool​::True␤Bool​::False␤Any␤»
* masak submits rakudobug
<masak> benabik++
<masak> b​: grammar G { rule TOP { a } }; say so G.parse("a"); say so
$/; say $/.perl
<p6eval> b 1b7dd1​: OUTPUT«Bool​::True␤Bool​::True␤Match.new(␤ from =>
0,␤ orig => "a",␤ to => 1,␤)␤»

From @jnthn

On Wed Dec 28 13​:34​:28 2011, masak wrote​:

<thou> are grammars known broken in current nom? e.g. this works in
rakudo-ng and not in rakudo-nom, for me​:
https://gist.github.com/1529700
<benabik> It seems to work if I set $/ to the return value of parse
<benabik> Perhaps there's a bug with $/ ?
<masak> yes, seems that way.
<masak> all the .parse calls come out as True in nom.
<masak> nom​: grammar G { rule TOP { a } }; say so G.parse("a"); say so
$/; say $/.perl
<p6eval> nom a9bead​: OUTPUT«Bool​::True␤Bool​::False␤Any␤»
* masak submits rakudobug
<masak> benabik++
<masak> b​: grammar G { rule TOP { a } }; say so G.parse("a"); say so
$/; say $/.perl
<p6eval> b 1b7dd1​: OUTPUT«Bool​::True␤Bool​::True␤Match.new(␤ from =>
0,␤ orig => "a",␤ to => 1,␤)␤»

Fixed​:

grammar G { rule TOP { a } }; say so G.parse("a"); say so $/; say $/.perl
Bool​::True
Bool​::True
Match.new(orig => "a", from => 0, to => 1, ast => Any, list => ().list,
hash => EnumMap.new())

Tagging testneeded.

/jnthn

The RT System itself - Status changed from 'new' to 'open'

From @moritz

This fixed allowed us to run advent2009-day10.t, which serves as a test
for this ticket now.

@moritz - Status changed from 'open' to 'resolved'